Home Physics Newton's Laws of Motion NTA Abhiyas Question The coefficient of friction between the two …
Physics Newton's Laws of Motion NTA Abhiyas Question MCQ (Single Correct)

The coefficient of friction between the two blocks shown in the figure is = 0.4 and between the lower block and the ground is zero. The blocks are given velocities of 2 m s -1 and 8 m s -1 respectively in the direction shown in the figure. In how much time (in seconds) the slipping between the blocks will stop?

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The correct answer is:
CHECK THE SOLUTION.

(l)

The common velocity of the blocks can be calculated as follows

3v = 1x2 + 2x8

v = 6 m s -1

The acceleration of the 1 kg block is

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